![]() So Boyle found PV = (nRT)īut did not explore the effect the temperature, or the number ofmoles would have on pressure and volume. In Boyle's experimentsthe Temperature (T) did not change, nor did the number of moles (n)of gas present. V(CO 2(g)) = 0.124 L at 25☌ and 100 kPa.That is, the product of the pressure of a gas times the volume ofa gas is a constant for a given sample of gas. What volume of carbon dioxide will be collected if the sample is pure calcium carbonate? We are reasonably confident that our solution to the problem is correct. Our "rough enough" answer of 0.125 L is very close to our carefully calculated answer of 0.124 L. Perform a "rough enough" calculation by rounding off the numbers:Īnd then manipulate the moles of gas so that it is in an easier form for quick "mental" multiplication and division, The volume of 0.00500 moles of gas (much less than 1 mole) will be much less than 24.79 L, and our calculated value of 0.124 L is much less than 24.79 L so the answer is reasonable. Is your solution to the question reasonable? At 25☌ and 100 kPa, the volume of 1 mole of gas would be 24.79 L (V m from data sheet) Yes, we have determined the volume of carbon dioxide that will be collected. Have you answered the question that was asked? Use the balanced chemical equation to determine moles of CO 2 producedġ mole CaCO 3 produces _ moles of CO 2Ġ.00500 mol CaCO 3 produces _ moles of CO 2Īssume no loss of CO 2(g), that is, all the gas produced is collected. ![]() Step 1: Calculate moles of carbon dioxide gas, CO 2(g), producedĪssume the CaCO 3 is 100% pure (no impurities).Īssume that the only source of gas being collected is the reaction given in the problem. What steps do you need to take to solve the problem? So, V m = molar volume of gas = 24.79 L mol -1 (from data sheet) n(CaCO 3(s)) = amount in moles of calcium carbonate = 0.00500 mol.formula for calcium carbonate: CaCO 3(s).All the CaCO 3 reacts (reaction goes to completion).What information (data) have you been given?ĬaCO 3(s) + 2HCl(aq) → CaCl 2(aq) + CO 2(g) + H 2O(l) What chemical principle will you need to apply?Īpply stoichoimetry (V (g) = n (g) × V m) V(CO 2(g)) = volume of carbon dioxide gas = ? L Substitute in the values and solve for volume of nitrogen gas:ĭetermine the volume of carbon dioxide gas if the calcium carbonate is pure.What is the relationship between volume of N 2 gas, V(N 2(g)), and moles of N 2 gas, n(N 2(g)), at a specified temperature and pressure?.Units are consistent so no conversion is necessary. Molar gas volume, V m is given in moles per litre So, V m = molar volume of gas = 22.71 L mol -1 (available on data sheet)Īmount of N 2(g) gas, n(N 2(g)), is given in moles What is the volume occupied by 3.70 moles of N 2 gas at STP?Ĭonditions: STP (Standard Temperature and Pressure, 0☌ and 100 kPa) Substitute in the values and solve for volume of helium gas:.What is the relationship between volume of helium gas, V(He (g)), and moles of helium gas, n(He (g)), at a specified temperature and pressure?.Units are therefore consistent and no conversion is required. So V m = molar volume of gas = 22.71 L mol -1 N(He (g)) = moles of helium gas = 0.50 molĬonditions: standard temperature and pressure (STP, 0☌ and 100 kPa) What information (data) has been given in the question?.A balloon contains 0.50 moles of pure helium gas at standard temperature and pressure.Ĭalculate the volume of helium gas in the balloon. Take the test now! Worked Examples of Calculating Volume of Gas Using Molar Volume of Gas
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